Notebook·PU-Mu 1050, Box 8, folder 5·June 1934–December 1935

B. H. Hill, I Site levels June 1934–Dec. 1935Bert Hodge Hill

·

Handwritten in English. Every line is transcribed, and the text sits beside the scan.

Scan 21 of notebook PU-Mu 1050, Box 8, folder 5 (B. H. Hill, I Site levels June 1934–Dec. 1935), handwritten in English. The transcription follows.

Scan: Penn Museum Archives, Philadelphia, PU-Mu 1050, Box 8, folder 5, Courtesy of the Penn Museum.

Page 47Scan 21 of 87

Drawing: geometric network of triangles with points C, D, E, G; labels: to 5, C, 39°30', 38°20', 84°53', D, 33°47', 185.74, 23., E, 56°47', C 123.°13, 297.83, 252.25, 17°17', G, K4; to the left of D: 113] | For calculation p. 44

3°15° Ls as shown in diagram (also as per revision pp 46)

Fin

C3A5=± 0=0/360
G?=3.15 R=176.45[brace left] ∠ = 39.00134
E3=35.58 L=215.55[brace left] ∠ = 38.20
D4=74.15 L=354.1577.20
D4C3=± 0∠ 84.55
G?=84.53 L=84.55∠ 33.45 / 118°40'129
E?=61.20 R=118.40
E4C3=± 0∠ 4-7-3 = 23°
D422.59 R=337.1∠ 3-7-9 = 98.45638
G9?81.15 R=98.45121.45
G-Kouklia 4=± 0
E?
D4=65.13 L∠ 17-17640
C3=82-30 L∠ 1-7
A5=83-37 L

Right page

Ls as recorded.

(p. 37)
A - C - G2.5 + 176.45 + 1.7 = 179.57
C - E - G39.13 + 98.45 + 17.17 + x = 155.15 + x
C - D - E38.17 + 118.40 + 22.59 = 179.56
C - D - G77.30 + 84.53 + 17.17 = 179.40
D - E - G33.47 + 121.44 + x = 155.31 + x

A C G & C D E check practically. | 179.57 179.56 Read: C D E = 38.20 + 118.40 + 23.0 = 180° & solve by law of sines, side C-D being 11.7 mm. Formula = q.v. A.B. a d = a / sin E · sin D c = a / sin E · sin C (180 c = 117.00 E = 23° C = 38°20' D = 118°40' get C-E = 262.74 (log 2.41952) D-E = 185.74 (log 2.26887)

65 figures hard to readstruck struck outadded written in above” jug ditto, and what it repeatsword reading not certain

Spotted a wrong reading? Write to us or use alexis@ancientcyprus.com