Unnumbered pageScan 31 of 87
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△ ACG \angles 2° 5' + 176° 45' + 1° 7' = 179.57 AC = 201.75 CG = 392.25 (Log 2.30481) (2.59356)
Assuming C correct solve for A & G 392.25 - 201.75 = 90.50 log 2.27989 + = 594. 277379 A + G = 3.15 9.50610 ½ = 1.37.30 Log Tan + 8.45135 7.95746 ½(A-G) = 0° 31' 10" \therefore A = 2° 8.40' + G: 1°.6-20
Sin 2° 8' 40 = 8.57308 1° 6' 20" 8.28543 2.30481 2.59356 . l for C to \\ line A-G \} 0.87789 0.87899 > 7.55 = 7.57
△ ADF angles (4.3712? ) 171° 371/2' , 3° 45' AD = 258.50 + DF = 312.70 - (Log 2.41247) (2.49513)
2.41247 Sin 3° 45 8.81560 3.59687 42/159 2.49513 Sin 839826 = ∠ 4° 32' 24"
. l to AF \\ fr - D \\ 20.45 \} 8.81560 2.49513 1.31073
If 3:45' correct D must be increased to c 171.42½ ADC will then be reduced to c 48.42½ . 139.35 \ 171.4212 \ 48.4212 \} = 360
Right page
Drawing: triangulation network; labels: D, 185.74, VIII, E, 76.56, c, E', F
∠ ED 8 = 9° 4' (70 WR - 41 20R 36) ∠ CED = 22° 59 . ∠ CE8 = 114° 35 \\ 8 Ec = 65° 25 \\ CEE' = 24° 49 \\ 8 EE' = 90.14 \} (p. 38) DEF 133.37 (p 45) EE' 8 = 34° 15' (p 39)
△ E E' 8: \angles: 90° 14 + 34:15 + \therefore 55° 31' E - E' 76.56
Log 76.56 = 1.88400 . S 55.31 9.91608 1.96792 34-15 9.75036 E 8 = 52.27 1.71828 Lt 90.14 = 0 E' 8 92.88 1.96792
Add \angles at. E 22.59 \\ 114.35 \\ 90.14 \\ 133.37 \\ \hline 361.25 ( p 34 ) EF 8 = 18° 55
∠ E' E F = 1° 25' \therefore FE 8 = 90.14 - 1.25 = 88.49 · F 8 E = 72° 36 EF = 154.23 (p 45) Log = 2.18818 S 72° 36 9.97966 2.20852 S 18.55 9.51080 1.71932 = 52.40
△ D E 8: \angles 9° 4', 137° 24 \therefore 33° 32 Log 185.74 = 2.26887 S 33° 32 9.74036 252851 S 9° 4' 9.19751 1.72602 = 53.21
To get 52.27 we should have to reduce ∠ at D to c 8° 55' Not impossible A bad shape anyhow
To make it 52.27 the base 154.23 must be reduced to 153.86 if \angles presumed exact
65 figures hard to readstruck struck outadded written in above” jug ditto, and what it repeatsword reading not certain